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Questions (3 pts. apiece) Answer questions in complete, well-written sentences WITHIN the spaces provided.
Problems. Clearly show all work for full credit.
1. (8 pts.) |
The work function of zinc is 3.6 eV. What is the energy of the most energetic photoelectron emitted by ultraviolet light of wavelength 2400? |
2. (17 pts) |
At it is known that of 800 neutrons in a one-dimensional box of width
, 500 have energy and 300 have energy .
The eigenfunctions and eigenvalues of the one-dimensional particle in a box
of width
are
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3. (17 pts) |
Find and at relevant to a one-dimensional box with walls at for
the following initial state.
Make sure you get an expression for valid for all eigenstates. The eigenfunctions and eigenvalues of the one-dimensional particle in a box of width are |
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Problems (continued). Clearly show all work for full credit.
4. (17 pts) |
In the phenomenon of cold emission, electrons are drawn from a metal at room temperature
by an externally supported electric field.
The potential well the metal presents to the free electrons before the electric field is turned on
is shown in Figure 1a below.
After application of the constant electric field
, the potential
at the surface slopes down
as shown in Figure 1b below, thereby allowing electrons in the Fermi sea to `tunnel'
through the potential
barrier.
If the surface of the metal is taken as the plane, the new potential outside the surface is
where is the Fermi level and is the work function of the metal.
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Problems (continued). Clearly show all work for full credit.
5. (17 pts) |
In solving the Schroedinger equation for the harmonic oscillator
potential we rewrote the Schroedinger equation
in the form
where , and . We then showed the asymptotic solution is We then made the guess that the initial wave function will be of the form where , is some, as-yet-to-be-determined function, and is a normalization constant. This guess was made in the hope of ensuring the finiteness of the wave function far outside the range of the potential. Starting from this form of the wave function and the Schroedinger equation, show the new differential equation we must solve is where |
The wave function, , contains all we know of a system and its square is the probability of finding the system in the region to . The wave function and its derivative are (1) finite, (2) continuous, and (3) single-valued.
Speed of light () | fermi () | ||
Boltzmann constant () | angstrom () | ||
electron-volt () | |||
Planck constant () | MeV | ||
GeV | |||
Planck constant () | Electron charge () | ||
Planck constant () | Electron mass () | ||
Proton mass () | atomic mass unit () | ||
Neutron mass () | Avogadro's Number | ||
() |